Python
Send Email
We will first import "request" and "json" module, as we need those module for calling the API
Then, we will import our own url function from a file called functions.py, which can be referred to in the "Common Stuff" section linked at the bottom.
We will create a function sendEmail.
Inside the function, we will create the input variables.
Then we build both the header and content object.
Then, we will create the final url, where we will use the url() function to get the API url, and append the headerObj and contentObj to the API url.
We will then post the final_url and store the server response in the variable "response".
The GlobalErrorID is then retrieved and stored in variable "errorCode".
If the errorCode is '010000', it means that there is no error, and we will display the result.
If the errorCode is '010041', it means that the OTP provided has expired. We will then display 'OTP has expired. You will be receiving a SMS'.
Else, we will display the ErrorText.
Entire Code:
import requests, json
from functions import url
def sendEmail():
#Header
serviceName = 'sendEmail'
userID = 'bobsmith1'
PIN = '123456'
OTP = '123456'
#Content
emailAddress = 'bobsmith@hotmail.com'
emailSubject = 'API Test'
emailBody = 'API Test'
headerObj = {
'Header': {
'serviceName': serviceName,
'userID': userID,
'PIN': PIN,
'OTP': OTP
}
}
contentObj = {
'Content': {
'emailAddress': emailAddress,
'emailSubject': emailSubject,
'emailBody': emailBody
}
}
final_url="{0}?Header={1}&Content={2}".format(url(),json.dumps(headerObj),json.dumps(contentObj))
response = requests.post(final_url)
serviceRespHeader = response.json()['Content']['ServiceResponse']['ServiceRespHeader']
errorCode = serviceRespHeader['GlobalErrorID']
if errorCode == '010000':
print("Email sent")
elif errorCode == '010041':
print("OTP has expired.\nYou will receiving a SMS")
else:
print(serviceRespHeader['ErrorText'])
sendEmail()
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